Hello, everyone.

This is Enta.

By the other day, we had finished installing the vertical beams for the frame.

This time it's the crossbeam, but it's just like last time, lol.

As mentioned last time, the crossbeam is 12 meters long.

12 m ÷ 5 m (length of rebar used) = 2 bars, with 2 m left over

There will be two places where the rebar overlaps.

5 m + 5 m + 2 m = 12 m

Since the overlap of the rebar is 0.52 m per location,

0.52 m × 2 locations = 1.04 m

2 pieces of rebar at 5 m each + 2 m + 1.04 m = 13.04 m

Since Frame 300 uses four reinforcing bars on the top and bottom,

13.04 m × 4 = 52.16 m per beam

Total Length ÷ Frame Spacing = Span

18 m ÷ 2 m = 9 spans

9 spans + 1 = 10 beams (same number of intersections)

10 beams × 52.16 m = 521.6 m

521.6 m × 0.995 kg/m (unit volume weight of D13 rebar) = 519 kg

Vertical and horizontal rebar for the curved section =545 kg + 519 kg = 1,064 kg

If you're going by the number of items,1,064 ÷ 5 m = 213 pieces

An experienced worker would adjust according to the undulations of the slope,

I think it should be fine to deliver the goods based on an approximate loss rate, but,

For now, I'll place an order for this quantity.

Considering the potential for loss, I think it’s better to place two orders.

See you later.

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Calculating Reinforcement for Formwork (Part 3) | Formwork Cross-Beam Reinforcement